Question

What is the formula equation for when Beryllium cloride reacts with silver nitrate?

Answer 1

Let's see, Be wants to give up two electrons and Cl wants to take one so we would have \[BeCl_2\] And silver nitric acid gives you\[AgNO_3\] During a reaction the compounds typically switch partners so you have\[BeCl_2 + AgNO_3 \rightarrow BeNO_3 + 2AgCl\] The first thing you have to do is balance it.\[BeCl_{2(s)} + 2AgNO_{3(aq)} --> Be(NO_{3})_{2(aq)} + 2AgCl_{(s)}\]
So what you get is an aqueous solution of beryllium nitrate with a silver chloride precipitate.