Question

I need to find the zeros of the function f
x)=(x+5)^2 +3.
Step by Step please!!!

Answer 1

this has no zeros, because no matter what x is
\[(x+5)^2\geq 0\] and so
\[(x+5)^2+3\geq 3\]

Answer 2

The answer was -5 +/- i squareroot 3. There was an imaginary number. Does that mean it uses the -b +/- squareroot b^2-4(a)(c) over 2(b)?

Answer 3

when you use the quadratic equation (the one you described above) you get \[-5 \pm i \sqrt{3}\]. Those are your zeroes, although you get an imaginary number, so it is a complex number

Answer 4

can you show me step by step?

Answer 5

I tried it myself but it didn't work out so well.