Mathematics
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OpenStudy (anonymous):
How do I make (k/2)(5k-1) + 5(k+1)-3 equal to ((k+1)/2)(5k+4)?
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OpenStudy (anonymous):
by multiplying both part of the equation by 2
OpenStudy (anonymous):
[k/2(5k-1)+5(k+1)-3 = (k+1)/2 (5k+4)\]
OpenStudy (anonymous):
How do I simplify the left side?
OpenStudy (anonymous):
before and after you simplify it, it doesn't matter. .
to solve, use only distributive property of multiplication. . . .
OpenStudy (anonymous):
I need to make the left side look like the right side
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jhonyy9 (jhonyy9):
k(5k-1)+10(k+1)-6=(k+1)(5k+4)
5k2-k+10k+10-6=5k2+4k+5k+4
5k2+9k+4=5k2+9k+4
0=0
OpenStudy (anonymous):
thanks
jhonyy9 (jhonyy9):
do yo understand it ?
OpenStudy (anonymous):
yeah you got rid of 2 by multipluying it, right
>?
jhonyy9 (jhonyy9):
you need multiply by 2 because 2 is denominator common
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OpenStudy (anonymous):
ok, thats the part i had trouble with
OpenStudy (anonymous):
that's what i'm talking about
thanks jhonny for expounding it. . .
jhonyy9 (jhonyy9):
after multiply term by term both sides and get that the left side is equal right side
jhonyy9 (jhonyy9):
yw jerwyn
OpenStudy (anonymous):
thanks again
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jhonyy9 (jhonyy9):
yw
jhonyy9 (jhonyy9):
medal ?
OpenStudy (anonymous):
done
jhonyy9 (jhonyy9):
ok good luck bye
OpenStudy (anonymous):
bye