Question

A crane lifts a 425 kg steel beam vertically a distance of 66 m. How much work does the crane do on the beam if the beam accelerates upward at 1.8 m/s2? Neglect frictional forces

Answer 1

How's work defined?

Answer 2

F=ma = 425kg x 1.8m/s² =blablabla
work done = force times distance=F x 66m=bla bla bla...

Answer 3

W=Fd=mad=425*1.8*66
=50490 J

Answer 4

not correct