Question

differentiation question:
A= 16cosx(1+sinx)
find dA/dx

Answer 1

its a product rule

Answer 2

\[A' = r'l+rl'\]

Answer 3

r = 16 cos(x)
l = 1+sin(x)

Answer 4

ideally, r and l stand for left and right; but they just look better as rl instead of lr :)

Answer 5

i tried that but i got the wrong answer

Answer 6

show me how you did it

Answer 7

-16sinx(1+sinx) + cosx(16cosx)

Answer 8

looks fine to me; did you simplify it any?

Answer 9

yeah i just multiplied it, but the answer is 16-16sinx -32sin^2x

Answer 10

-16sinx(1+sinx) + cosx(16cosx)

-16 sin(x) -16 sin^2(x) + 16 cos^2(x)

-16 sin(x) -16 sin^2(x) + 16 (1-sin^2(x))

-16 sin(x) -16 sin^2(x) + 16 - 16 sin^2(x)

16 - 16 sin(x) - 32 sin^2(x)


its not that the answer is wrong; just misshapen

Answer 11

thanks!

Answer 12

youre welcome :)