Question

See attachment

Answer 1

Remember, here the coefficient of x^2 (leading coefficient) is -1.
If the leading coefficient is negative, it is a maximum.
If the leading coefficient is positive, it is a minimum.

Answer 2

so its minimum?

Answer 3

If the leading coefficient is negative, it is a maximum.
Try again!

Answer 4

im confused!! where r u getting the negative from?

Answer 5

In the equation/expression,
ax^2+bx+c,
a is the leading coefficient, namely the coefficient of the highest-degree term.
So in
-x^2+2x+6,
(-1) is the coefficient of x^2, and it is negative, so the curve has a maximum.

Answer 6

ok so witch graph is the right one?

Answer 7

Since it has a maximum, so it cannot be B & D.
Choose from A or C bearing in mind that you said the line of symmetry is x=1.

Answer 8

OK, I see what you mean.
It is clearly not A, because the line of symmetry is at x=-1.
C seems to show the line of symmetry at x=0, but I think it's a misprint, or the figures do not correspond to the question.

Answer 9

Your best bet is C, if it is computer homework.

Answer 10

Ok thx

Answer 11

By the way, the vertex should (normally) tell you which graph to choose (except for max/min). In this case, because of the misprint, it's normal that you have difficulty in making a choice.

Answer 12

You're welcome!