Find the point in which the line that passes through the points (1,0,1) and (4,-2,2) intersects the plane x+y+z=6
Write the equation for the line in parametric form. Then solve for when the ordinates of that form sum to 6.
okay thx dude
would one of the parametric forms be: x = 1 + 3t y = -2t z = 1 + t ? I also need to study this some time..
yes
so we set the parametric equation = to 6 and solve?
or set t=6?
You set x + y + z = 6 and solve
Which makes sense as it is the only other piece of information you actually have in the problem.
so (5/3, -3, 5)?
-2 sorry
(5/3, -2, 5)
What are your equations for the parametric form of the line?
i'm using the parametric equations above...then setting 6 = 1+3t, 6= -2t, 6 = 1+t and solving each for t
No, you're not thinking.
For each value of t (x,y,z) = (1+3t, -2t, 1+t) is a point on the line.
it cannot be that t is different for each ordinate; i.e., x doesn't have one value of t and y another etc.
Do you understand where that parametric form comes from?
okay...i just figured it out lol
So what's your final answer?
hang on i'm writing it out
on paper first
okay..so the line intersects the xy plane when z = 6 correct?
No. I recommend you go back and read the section in your book on the parametric form of lines.
or z = 0
No.
u get anywhere with it ska?
1+3t -2t + 1+t =6 ? Then solve for t. when you solve t, plug it into this: (1+3t, -2t, 1+t)
oh i have no idea...was just asking if you got anywhere with it...a shame he's the only one that can help with calc 3
What slaaibak suggests is exactly right. You need to convince yourself that this makes sense.
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