Question

Solve the following system equations:
2x + 4y – 3z = –7
3x + y + 4z = –12
x + 3y + 4z = 4

POSIBBLE ANSWERS:

(–6, 2, 1)

(6, 2, 1)

(6, –2, –1)

(–6, –2, –1)

Answer 1

when in doubt, plug in the answers to see what fits

Answer 2

there are 2 ways to go about this. you can do trial and error with the 4 different possible solutions or you can actually solve the equations

Answer 3

trial and error is the easiest way to go lol

Answer 4

a can tell right now that the last 2 options are off the table

Answer 5

lol solving three equations would take your breath away, rather u will solve 4 other questions with trial and error

Answer 6

the 2nd one falls flat as well, id test the first to be sure

Answer 7

to solve the equations you need to solve for a variable via 2 equations and then substitute it in the other one. the easiest way to do this is take bottom 2 equations. multiply 2nd one by (-1)

Answer 8

-6,2,1??? AM i correct?

Answer 9

the first one satisfy the equation

Answer 10

dunno, but i think its your best shot

Answer 11

but u can solve it bu cramer or gous rules

Answer 12

\[(-1)(3x + y + 4z = –12) = -3x-y-4z=12 add this to bottom eqn to cancel out z's

Answer 13

taking test and doing math are 2 seperate entities ;)

Answer 14

For the trial and error, you can add up the equations to make a new one,
6x+8y=5z=-15
and you need to test only once for each choice.

Answer 15

thank you everyone.. medals for all my helpers