Question

integral of: sin^4 dx

Answer 1

look in back of the book for the "reduction formula" for sine

Answer 2

See this is what I did, is it correct?

Answer 3

pɐǝɹ oʇ pɹɐɥ ʎɹǝʌ sı sıɥʇ

Answer 4

then rotate it :)

Answer 5

:P Its just the way my scanner does it

Answer 6

I'm at college atm, and their scanner is funky

Answer 7

That's correct.

Answer 8

By the way, nice handwriting.

Answer 9

Thanks, the one thing I wasn't sure about it was this:

Answer 10

\[\int sin^n(x)dx=-\frac{1}{n}sin^{n-1}(x)cos(x)+\frac{n-1}{n}\int\sin^{n-2}(x)dx\]
maybe

Answer 11

No because\[(1-\cos(2x))^2=1-2\cos(2x)+\cos^2(x).\]

Answer 12

Ah, I see

Answer 13

Thanks guys

Answer 14

Typo on the last term above, but you're welcome.

Answer 15

i think there is a mistake : sin^2 (x)= (1-cos(2x))/2

Answer 16

Isn't that what he wrote?