Question

Add and write in simplest form:

Answer 1

\[5x+1 \over 2x+1\]+\[3x+1 \over 2x+1\]

Answer 2

A. 4
B. \[2 \over 2x+1\]
C. \[8x+2 \over 2x+1\]

Answer 3

do you just want an answer, or learn how to do it?

Answer 4

I want both.

Answer 5

well first make sure the denominators are the same; then add the numerators together.

Answer 6

How do I do that tho ?

Answer 7

which part?

Answer 8

Both

Answer 9

do you know which part is a denominator?

Answer 10

The bottom parts of the problem

Answer 11

are they the same for both terms?

Answer 12

Yes

Answer 13

OK, so since they're the same, you can add the numerators together

Answer 14

Yes

Answer 15

ok, so what do you get when you add the numerators together

Answer 16

I got \[8x+2 \over 2x+1\]

Answer 17

great , so that' one of your answer choices

Answer 18

Alright but then it says to write it in simplest form.. what do I do to get into simplest form, IF the answer I got isn't simplified enough?

Answer 19

find a factor that can be factored out of both the numerator and denominator

Answer 20

I'm confused with that now

Answer 21

well if the denominator (in theory) were 2x+16, you could factor out a 2, and get 2(x+8).

Then in the numerator you could factor out a 2 and get 2(4x+1).

The 2's would cancel, so you'd end up with
\[ {4x+1} \over {x+8} \]

Answer 22

So my answer would just remain what I have then right?

Answer 23

yeah, for the problem you gave it can't be reduced further