Subtract and give the answer in simplest form:
\[3x \over x-5 \] - \[5 \over 5-x\]
A. 3 B. \[3x-5 \over x-5 \] C. \[3x+5 \over x-5\]
ok this one is more complicated since the denominators are not the same. So to make them the same multiply the first expression by 5-x / 5-x, and the second one by x-5 / x-5. Then, the denominators of both terms will be the same -- (x-5)*(5-x), and you can then add the numerators together.
That completely just confused me /: It was just like all twisted up when I thought about it. Blaaaaah ):
which part confused you?
How to get the same denominators
here's a way to think about it. imagine you are trying to add two fractions, e.g. 1/5 + 1/6. how do you add those?
2/11
no - you can't just add the denominators. for example, what's 1/2 + 1/2? it's not 2/4, right?
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