HELP PLEASE WITH PHYSICS :/
A soccer player kicks the ball at an initial velocity of 20.0 m/s^2 at an angle of 37.0
Calculate the magnitude of his horizontal velocity when the ball reaches its maximum height, How far does the ball land?
First, we need to break the initial velocity up into its vertical (y) and horizontal (x) components. Do this and we'll move on.
\[x=v_{0x}t+\frac{1}{2}a_{x}t^{2}\] since acceleration in x is 0: \[x=v_{0x}t~Equation~1\] \[v_{y}=v_{0y}+gt\] \[t=(v_{y}-v_{0y})/g\] \[t=(v_{y}-v_{0y})/g\] since the y velocity at the midpoint of the projectile motion is zero (stationary): \[t=-v_{0y}/g~Equation~2\] Solve the system of Equation 1 and Equation 2: \[x=-v_{0x}v_{0y}/g=-v_{0}cos(\theta)v_{0}sin(\theta)/-9.80~m/s^{2}\] \[x=20~m\]
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