Question

solve for L

R=r+400(W-L)/N

Answer 1

is the little r over the N as well?

Answer 2

no its seperate

Answer 3

R = r + 400((W-L)/N

R = r + (400W - 400L)/N

R = r + 400W/N - 400L/N

R - r - 400W/N = -400L/N

N*(R - r - 400W/N) = -400L

(N*(R - r - 400W/N))/-400 = L

Answer 4

To elaborate on my answer:

R = r + 400((W-L)/N

R = r + (400W - 400L)/N (distributed the 400)

R = r + 400W/N - 400L/N (divided both terms in the parenthese by N)

R - r - 400W/N = -400L/N (move everything but the term with L, to other side)

N*(R - r - 400W/N) = -400L (multiply both sides by N)

(N*(R - r - 400W/N))/-400 = L (divide both sides by -400)

Answer 5

Could you go (NR - Nr - 400W)/-400 = L ?

Answer 6

yeah, i suppose you could distribute the N if you want also. either way :).