Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

Lim 1- cos(4x)/sin (2x) x>0(X tends to 0)

OpenStudy (anonymous):

its 0

OpenStudy (anonymous):

yes, I see that but I am just wondering whether to just plug x=0 into the expression or is there an intermidiate step where we have to simplify or ...............

OpenStudy (anonymous):

first consider the function [1- cos(4x)]/sin (2x)= [1-cos^2 2x +sin^2 2x]/sin2x =2sin^ 2x/sin 2x = 2 sin 2x now apply the limits, you will be getting 0

OpenStudy (anonymous):

!!!!!!!!!!!!!GOT IT !!!!!!!!!!!!!!!!!

OpenStudy (lalaly):

do u know lhopitals rule?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!