Can someone tell me how to simplify radicals? its on my final today and my teacher didnt even teach it
what kind of radicals
like radical 60x4y2
thats x to the 4th power
\(\sqrt{60x^4y^2}\) note that 60 is \(2^2 * 3 * 5\)\[=\sqrt{2^2 * 3 * 5 * x^4 * y^2}\]\[=2x^2|y|\sqrt{15}\]
wait why is it 2 to the 2nd power?
the general rule is to look for parts of the expression that you can easily take OUT of the square root sign. for example, \[\sqrt{60}\] = \[\sqrt{4*15}\] =\[2\sqrt{15}\]
2 to the 2nd power = 4 4*3*5 = 60
oh i see
you have to break it down until you can take things out of the square root sign, like an X^2 can be taken out of the square root sign and turned into an X.
does that make sense aavarino?
yes
so you even do the square root of the exponents
im learning this on my own my teacher didnt even show us how to do these lol
and to simplify should all the variables be outside of the radical?
yup! exactly. \[\sqrt{x ^{4}}=x ^{2}\]
the goal of simplifying is to get AS MUCH AS YOU CAN out of the radical sign.
\[\sqrt{y ^{2}}=y\]
it's possible that a variable (x or y) may be left inside the radical sign, and that's okay, as long as it's as simple as you can make it.
\[\sqrt{27x ^{4}y}\]
for that one is it \[3x ^{2}y \sqrt{3} ? \]
or did i do it wrong lol
ALMOST, you're very close. the y that is under the radical - you can't reduce that any further. so it stays under the radical along with the 3 you already have under there.
oh!! i gotcha so whatever is already simplified leave in the radical
IF IF IF it was a y^2 under the radical, then you can reduce that to just y, but it isn't in this probelm.
yes, if it's in there to begin with, it must stay in there. it's like a box. you want to take out the stuff you can, and what's left inside is already as simple as it can get. like a 3, or a y. if you have a 4 left in there though ,then you have to take it out (square root of 4 = 2).
can i give you another one to see if you can do it now?
yes please!
this one is hard, but i think you can do it: \[\sqrt{40x ^{3}y ^{4}}\]
wait quick question before i do it.. since 40 has a lot of factors can i choose any? would i get the same answer if i chose 10 and 4 or 8 and 5?
great question! sure, just remember that what's left in the radical has to be as simple as possible. so let's say you break 40 down into: 8 and 5. MAKE SURE YOU NOTICE that 8 can then be further broken down into 4 and 2. so really, 40 can be broken down into 4 and 2 and 5. OR 40 can be broken down into 4 and 10. try it both ways, and see if you get the same answer. :-)
\[2y ^{2} \sqrt{4x ^{3}} ?\]
oops i lied
i meant 2 in the radical lol
let's look at just the X^3 under the radical for a second: \[\sqrt{x ^{3}} = \sqrt{x ^{2}x}\] how would you reduce that part?
i thought 3 didnt reduce? but the x^2 reduces to x
the second part is right, but X^3 is the same as X*X*X = X^2*X all those expressions are the same.
ohhhh
so how would the answer look from the question before?
you had some part of it right: \[2xy ^{2}\sqrt{10x}\] make sure you can get to that, and if not, ask me for more help please :-)
question.. but cant 10 be simplified?
it can be broken down into 5 and 2, however neither of those is a clean square root so it doesn't make it any simpler. (good question!)
oh ok! for not learning this in class i understand now
well getting the hang of it
great! should we try another one?
i have 2 more on my review sheet. \[\sqrt{100x}/121 \] ( not sure how to do a fraction on here )
\[\sqrt{100x}/121\] like that?
yes
but its all in the radical
oops, that's what i was going for :-)
okay, so can either 100, x, or 121 be reduced?
yes 10, and 11
awesome. but as you noticed the X has to stay inside the radical.
so what would you get?
radical 10x/11 ? does the radical go over the whole fraction?
note that \[\sqrt{100}= 10 the 10 is OUTSIDE the radical. same for the 11.
so the x is the only thing that stays in the radical?
yup!
so you should have |dw:1323867417793:dw|
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