Question

if, a*b=48 and a^2+b^2=100, find value of a and b?

Answer 1

plz help

Answer 2

Mk, looking at the first problem, do you know how you would solve for a?

Answer 3

a = 48/b
a + b = 10 if you take the square root of both sides of the second equation

Answer 4

Now you have 2 equations and 2 unknowns

Answer 5

following?

Answer 6

simaltaneously solve them

Answer 7

a+b=10 and a*b=48?

Answer 8

a = 48/b

Answer 9

from there, substitute a = 48/b into a+b=10

Answer 10

Which will be
48/b + b = 10

Answer 11

but how does one get a+b=10 from a(square)+b(square)=100

Answer 12

if, a*b=48 and a^2+b^2=100, find value of a and b?

\[a=\frac{48}{b}\]
\[\left(\frac{48}{b}\right)^2+b^2=100\]

solve for b

Answer 13

I get b=-8,-6,6,8

Answer 14

solving it, gives (2304/b^2)+b^2=100,, right?

Answer 15

solving it, we get b^2-10b+48=0 !!!!

Answer 16

is this right?

Answer 17

no