Question

How do you raise a complicated fraction like 5x^4/4y^8 to the power of -2?

Answer 1

the rules dont change by complexity

Answer 2

\[(B^m)^n=B^{m\ *\ n}\]

Answer 3

But those aren't negative...

Answer 4

they are "any" numbers

Answer 5

So I just add negative two the exponents already present?

Answer 6

\[(\frac{5\ x^4}{4\ y^8})^{-2}\]
\[\frac{(5)^{-2}\ (x^4)^{-2}}{(4)^{-2}\ (y^8)^{-2}}\]
\[\frac{5^{-2}\ x^{4(-2)}}{4^{-2}\ y^{8(-2)}}\]
\[\frac{5^{-2}\ x^{-8}}{4^{-2}\ y^{-16}}\]
and flip as needed

Answer 7

Okay, times them - and 'flip as needed', flip to get the exponents to be positive?

Answer 8

yep

Answer 9

Okay! Thank you!

Answer 10

youre welcome