When simplifying (3-7/x)/(x+5/6x), do you times all the bits of the fraction by 6x to get rid of the fractions in the fraction, or do you times the top by x and the bottom by 6x?

Question

lalaly · Answer

is it$$\huge{\frac{\frac{3-7}{x}}{\frac{x+5}{6x}}}$$

anonymous · Answer

No, its (3-(7/x)) / (x + (5/6x))

lalaly · Answer

$$\huge{\frac{3-\frac{7}{x}}{x+\frac{5}{6x}}}$$

lalaly · Answer

?

anonymous · Answer

yeah, sorry. Thanks for clarifying.

lalaly · Answer

:D its ok 
you multiply top and bottom by 6x

anonymous · Answer

won't that leave the top with a fraction? Wouldn't the top be 18x- (42x/6) or something?

lalaly · Answer

it will be like$$\frac{18x-42}{6x^2+30}$$ then y can divide them all by 6 u get $$\frac{6x-7}{x^2+5}$$

lalaly · Answer

sorry the first one is 3x not 6x

anonymous · Answer

I see! Thank you!

lalaly · Answer

ur welcome :D

lalaly · Answer

i made a miistake :S

lalaly · Answer

its supposed to be$$\frac{18x-42}{6x^2+5}$$because the 6x cancels

anonymous · Answer

Ohh, right. Okay. You're right. I missed that too. :)
Thanks.

lalaly · Answer

im sorry:)

anonymous · Answer

That's okay! I'm grateful for the help!

lalaly · Answer

=),=)

anonymous · Answer

So is it -4/x+5, I wonder?