Question

Find the exact value of sin(T -pi/6) when sin(t)=1/3 and cos(t)=Rad8/3

Answer 1

\[sin(a+b)=sin(a)cos(b)+sin(b)cos(a)\]

Answer 2

in this case: a = T and b = -pi/6 but not sure if that fits too well

Answer 3

that might work, even with the funny looking decimal

Answer 4

ops there is a error there i will correct that

Answer 5

what funny looking decimal?

Answer 6

T=t?

Answer 7

\[\sin(T - \pi/6) = \sin(T)\cos(\pi/6)-\sin(\pi/6)\cos(T)\]\[\sqrt{3}/6 - 0,0232 = 0,2654\]

Answer 8

so basically use the double angle formula?

Answer 9

yes

Answer 10

\[\frac{1}{3} \cdot \frac{\sqrt{3}}{2}-\frac{1}{2} \cdot \frac{\sqrt{8}}{3}\]

Answer 11

oh did you get that from a chart myininaya?

Answer 12

Remember that \[\sin(a \pm b)= \sin(a)\cos(b) \pm \sin(b)\cos(a)\]

Answer 13

ok.. yes

Answer 14

yep bella
\[\cos(\frac{\pi}{6})=\frac{\sqrt{3}}{2}; \sin(\frac{\pi}{6})=\frac{1}{2}\]

Answer 15

ok thank you!

Answer 16

across the pond they use the "," as a "."