Evaluate: lim (x^2 +6x +5)/(x^2-3x-4) x--> -1
Okay so here you have to factor the function so that you can cancel out some parts of the equation and avoid dividing by zero.
LagrangeSon, you cannot, because in that case you would be dividing by 0. Rather, factor the two polynomials:
lim x-> =-1 (x+1)(x+5)/(x-4)(x+1)
Now you can cancel out the (x+1)'s in the numerator and denominator and plug in -1 to get your answer.
And, you should get, 4/-5 = -4/5
so - is the answer---f(x) = - 4/5 as x approaches -1? this sounds stupid, but I'm not sure how to notate it- what's the correct way to write the answer?
It's not a stupid question -- in most Calculus classes professors will penalize you harshly for incorrect notation. Yes, I would say that: lim write the function here = (-1+5)/(-1-4)= 4/-5 = -4/5 x->-1
The answer is just a number.
thanks very much
You're welcome. Good luck on your final. (I have a Calc I final tomorrow, haha).
Where is your final? - what school?
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