Simplify the expression and combine like terms. 4y^2-3y^3-6y^2+6y^3=
I'm going to report you for abuse because I answered this identical question about 10 minutes ago for you.
i had a question about that and you never answered.
i'm trying to understand one thing ..
I'm sorry -- what do you need help with?
i wanted to knw how you got rid of the y^3
I didn't get rid of it, I just factored it out of the equation. When you have variables across an entire function (the equation you posted is a function), you can pull them out and multiply it by the entire function, like this:
\[y^2(4 + 3y - 6 +6y)\]
Oops, that should be 4 - 3y, not 4 + 3y at the beginning. Still though, the principle is the same.
oh, okay. thank you !
If you multiply that \[y ^{2}\] across everything in the parentheses you'll get what you started with. And that's how you factor. Just like how 2 x 2 x 2 = 8. You can do this: 2(2 x 2) = 8
You're welcome. Sorry about the confusion.
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