Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

Simplify the expression and combine like terms. 4y^2-3y^3-6y^2+6y^3=

OpenStudy (anonymous):

I'm going to report you for abuse because I answered this identical question about 10 minutes ago for you.

OpenStudy (anonymous):

i had a question about that and you never answered.

OpenStudy (anonymous):

i'm trying to understand one thing ..

OpenStudy (anonymous):

I'm sorry -- what do you need help with?

OpenStudy (anonymous):

i wanted to knw how you got rid of the y^3

OpenStudy (anonymous):

I didn't get rid of it, I just factored it out of the equation. When you have variables across an entire function (the equation you posted is a function), you can pull them out and multiply it by the entire function, like this:

OpenStudy (anonymous):

\[y^2(4 + 3y - 6 +6y)\]

OpenStudy (anonymous):

Oops, that should be 4 - 3y, not 4 + 3y at the beginning. Still though, the principle is the same.

OpenStudy (anonymous):

oh, okay. thank you !

OpenStudy (anonymous):

If you multiply that \[y ^{2}\] across everything in the parentheses you'll get what you started with. And that's how you factor. Just like how 2 x 2 x 2 = 8. You can do this: 2(2 x 2) = 8

OpenStudy (anonymous):

You're welcome. Sorry about the confusion.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!