Consider dy/dx = 1/2x + y -1 a) Find the values of the constants m and b, for which y = mx+ b is a solution to the differential equation.
I got the same thing but I can't find out the value of b or m?
There's another part of the question before this one. But I don't know if it's related to solving this one. I'll put in out just in case. Let y = f(x) be a particular solution to the differential equation with the initial condition f(0) = 1.
let's plug in y(0) m=b-1
Where did the x go?
let's plug in y(1) m= 1/2 +(m+b) -1 1/2 + m+ b -1 two equation two unkown
I plug in 0 for x in first one, 1 for x in second one
\[m\to -\frac{1}{2},b\to \frac{1}{2}\]
y= -1/2 x + 1/2 should work
Thanks, I get it. But, if I face something on this level on my midterm, I think I'm still going to get roasted no matter how much I study.
what class is that from?
calculus
oh, I've taken differentials, even then It took me some time as you can see
There's a class called differentials? Wow. I'm just in plain calculus ab/bc. There's always some little holes I drop into when I do math.
Join our real-time social learning platform and learn together with your friends!