A block is sent up a frictionless ramp along which an x axis extends upward. The figure below gives the kinetic energy of the block as a function of position x; the scale of the figure's vertical axis is set by Ks = 46.0 J. If the block's initial speed is 4.50 m/s, what is the normal force on the block?

Question

anonymous · Answer

can we see the figure?

anonymous · Answer

attachment

anonymous · Answer

hmmm would the slope of the line be the coefficient of static friction?

anonymous · Answer

wait no lol that was stupid of me...frictionless ramp -.-

anonymous · Answer

the only other force acting on the object would be gravity. to find the normal force you need to find the total force in the y direction

anonymous · Answer

slope or gradient = force, (note that work done = F x distance)

anonymous · Answer

|dw:1324111373818:dw|Find the velocity at distance x by using KE.Then find acceleration that is equal to gsin$$\theta$$. Find $$\theta$$ in terms of m(mass of block). Finally find the normal force=mgcos$$\theta$$.