y<= –x + 7 y < 3x + 11
How do I solve?
solve for a variable and put it into the other
as a system? or independently?
As a system
what imasofty said...
wait, is one <= and the other just < ? or is that a typo?
one is less then or equal to and the second one is just less than
hm.... that throws me so I'm not sure, sorry. I just did this: solve y<= –x + 7 for x and plug it into the other inequality, which gave me y<8 but I think that may wrong because it doesn't take into account the <= sorry... I won't tell you I know if I'm not sure.
yea theres somthing funny you gatta do...its from pre calc i think
Im in alg II not precalc!
moneybird is on the case, he should know what to do...
thank you moneybird
thank you everyone who is trying to help me!
what i would have done is used a graph to solve it and got the answer on a graph paper, would have much simpler
how do i graph it? y=mx+b?
you can graph it by finding the intercepts on the x and y axis
turning test will help you graph it he knows that :D lol turning you should have known this man u r better than me :D i need to go tc Sweden :D
lol yes you do@ Akshay Budhkar... but im in USA now
No, I think you and I are pretty close @akshay anyway, yes you can graph the individual lines like y=mx+b then use the inequality properties to find the solution area. I don't want to go through that step-by-step, but I'll see if I can get wolfram's answer: http://www.wolframalpha.com/input/?i=%5By%3C%3D+%E2%80%93x+%2B+7+%26%26+y+%3C+3x+%2B+11%5D
ok, here's what I got all I see to do is to find the intersection of the two lines: 3x + 11= –x + 7 which is (-1,8) the intercepts of y=-x+7 are x=7 y=7 (that doesn't seem to matter here though) the x-intercept for y=3x+11 is -11/3 now all I can think to myself is that the graph looks something like this:|dw:1323990384266:dw|...
Join our real-time social learning platform and learn together with your friends!