Question

can someone help me solve the general solution of this DE:

y" + 3y' +3y = 0

Answer 1

\[r^2+3r+3=0\]now u solve for r using the quadratic formula

Answer 2

u get two complex solutions
r=\[\pm a+bi\]and the general solution will be\[y=c_1e^{ax}\cos(bx)+c_2e^{ax}\sin(bx)\]

Answer 3

i dont know about the eigen values, but i think thats the easier way

Answer 4

fair enough, thank you.

Answer 5

:)