Sequence/recurrence relation. Find the value of t(5) if t(n+1) = 3t(n) + 2. Note the numerals in brackets are supposed to be little underneath numbers.
\[t _{(n+1)}=3t _{(n)}+2\]
?
oh wait I can write it now with equation
but how you you do it?
do the problem or write out the equation?
Do the problem. I don't get it really.
i was first seeing if what i typed is how the problem looks like, is it correct? ^^^
\[t _{5}\]
yes that is right. That is the problem. It is a sequence equation.
ok
so what is \[t _{5}\]?
Shouldn't \[t_{5}\] be 14? But he answer says no.
that is the term. if \[t _{0}\] is the first term, \[t _{5}\] should be the sixth term
Oh sorry \[t _{1}=1\]
ok
you're suppose to get an answer without variable t?
\[t _{1} = 1\] Yeah I don't really get it. I think t is just really like the bit under the t.
can you upload an image of the question?
Not really capable. But that is all the question really says, excpet there is a whole tutorial section right before it, trouble is I don't understand it. There is an example kind of like this: if the rule is \[t _{1}= 1 and t _{k+1} = 2t _{k}\] then \[t _{1}=1, t _{2} = 2t _{1}= 2, t _{3}= 2t _{2}=\]4
so \[t _{5} should be 4t _{4}\]
why? I don't know. The answer is supposed to be 161
so the first thing to do is find what \[t _{_{(n+1)}} is....t _{(5+1)}=?\]
i was following the logic from your tutorial, it's set up the same way
\[3t _{4} + 2\]
no we're both wrong it's \[2t _{3}\]
+2
if you want to see step by step,\[t _{1}=1\] \[t _{2}=2t _{1}=2 t _{1}=1\] so just plug 1 in which would make it 2*1
\[t _{3}=2t _{2}=4\] \[t _{4}=2t _{3}=8\] \[t _{5}=2t _{4}=16\]
note that i didn't +2 in any one them...i just realized
but just follow the same logic
I'm getting there lol thankyou for the help!
np
t(1)=1 t(2)=3t(1)+2=5 t(3)=3t(2)+2=17 t(4)=3t(3)+2=53 t(5)=3t(4)+2=161
thanks mathmate. I have now understanding of this.
Good! Glad to be of help!
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