Use the definition of the derivative to find the derivative of f(x)=6
zero
0
Totally zero
rate of a constant =0
How do I know its zero? how do you find that?
becuase the derivative of any constant is 0 ...like 6 or 7 or 5000000
what if F(x)=2x^3-1
6x^2
how do u know that?
you need to calculate: \[\lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}\] knowing that:\[f(x)=6\] so \[f(x+h)=6\]
that is the definition of a derivative.
brought the exponent down and multiplied it to the coefficient then subtracted the exponent by one
it seems like the poster is just learning the rules of the derivative, so posting rules that we all know about derivatives isnt what he/she is looking for.
yes ive just started learning derivatives
Since f(x) = 6, is the constant function, f(anything) = 6. So when calculating the limit we obtain: \[\lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}=\lim_{h\rightarrow 0}\frac{6-6}{h}=\lim_{h\rightarrow 0}\frac{0}{h}=0\]
You need to do it from first principals lim(f(x+h) -f(x))/h as h --> 0 lim(6 - 6)/h = 0/h = 0 fx = 6 f(x+h) = 6
thank you!
if it was f(x) = x +6 it would be lim((x +h +6) - x +6)/h lim(h/h) = 1
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