Question

vector A has components Ax=1.30cm, Ay= 2.25cm; vector B has components Bx=4.10cm, By=-3.75cm.

Find a. the components of the vector sum A+B;
b. the magnitude and direction of vector A+B;
c. the components of the vector difference B-A;
d. the magnitude and direction of Vector B - A.

Answer 1

A=<1.3,2.25>

B=<4.1,-3.75>


just add component by component

A+B=<1.3+4.1,2.25-3.75>

<5.4,-1.5>

For magnitude

\[\sqrt{(5.4)^2+(1.5)^2}\]

for direction
\[tan^{-1}(-1.5/5.4)\]

Answer 2

whar? we have different answers

Answer 3

let me see what you do

Answer 4

the formula to get the vector is \[vector A= \sqrt{Ax ^{2}+ Ay^2}\] and \[Vector B= \sqrt{Vx^{2} + Vy^{2}\}

Answer 5

that will find you magnitude of vector A only

Answer 6

and vector b=\[\sqrt{Bx^2+ By^2}\]

Answer 7

oh ,you will add it afterward

Answer 8

just add it? so I came up with vector A=2.6 and vector B=5.56 so vector A + vector B = 2.6 + 5.56=8.16?

Answer 9

I think you are better off adding two vector component by component and then taking mag

Answer 10

I think that part is on how to get the magnitude. right?

Answer 11

magnitude of A+B

Answer 12

yeah so the magnitude is \[\sqrt{(5.4)^2 + (-1.5)^2}\]?

Answer 13

Yes

Answer 14

will I do the same thing on part c and d?

Answer 15

hey, ahmm, accordingly, when u get the magnitude, the formula for x-comp. is A cos \[\Theta\] right so we need to find the angle before we get the magnitude?

Answer 16

oh , if you are given magnitude and direction , yes

Answer 17

i dunno what to do. what will be my answer on letter b. drivin me crazy.

Answer 18

how can I get the value of x-component if the angle is not given. and it's impossible to compute the direction first because it needs the value for both x and y components