Question

I need help from with a problem from Yale Open Course
Romeo is at x=0m at t=0s when he sees juliet at x=6m.
a) romeo begins to run towards her at v = 5 m/s. Juliet, in turn begins to accelerate towards him at a =-2m/s^2. when and where will they cross?
b) suppose, instead, that juliet moved away from romeo with positive acceleration a. Find a(max), the maximum acceleration for which romeo can catch up with her. for this case find the time t of their meeting. show that for smaller values of a these star-crossed lovers cross twice.

Answer 1

try setting up an equation for both then setting the equations equal to each other.

Answer 2

ehh i said screw it after a couple of tries with the equations so i turned to my calculator and i got it to be at 1 secound. i used the mechanic formulas and i used t for x and at one secound romeo traveled 5 meters and juliet traveled -1 meter thus adding to the 6 meters.

Answer 3

lol....she runs away....haha why cant my physics problems be this funny?

Answer 4

haha... So time will be same then? i'll try to come with an equation for time for romeo and juliet and set them equal to each other.

Answer 5

ok i used d=v(0)t+1/2at^2 for both and plugged them into my calc

Answer 6

v(0)="v"knot...btw

Answer 7

nottation through a keyboard is hard

Answer 8

Thanks!!! :)