Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (2bornot2b):

Why is exponential function for complex variable defined so?

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

!!!!

OpenStudy (2bornot2b):

Do you know the definition for exponential function for complex variable?

OpenStudy (anonymous):

\[e^{i\theta} = \cos\theta + i\sin\theta\]?

OpenStudy (anonymous):

\[e^{i\theta} = \cos\theta + i\sin\theta= z\]

OpenStudy (2bornot2b):

Its not the exponential function for a complex variable. Its just another way to write a complex number.

OpenStudy (anonymous):

no, I don't

OpenStudy (anonymous):

then what is the exponential function for a complex variable?

OpenStudy (2bornot2b):

Suppose \[z=x+iy\] Then \[e^z=e^x(cos(y)+isin(y))\]

OpenStudy (2bornot2b):

The text has turned to be too small, so I am writing it again \[e^{x+iy}=e^x(cos(y)+isin(y))\]

OpenStudy (2bornot2b):

are you getting me now?

OpenStudy (2bornot2b):

By the way, did you all know the definition for the exponential function for a real variable?

OpenStudy (anonymous):

Nope :-D

OpenStudy (2bornot2b):

Suppose x is a real variable Then \[e^x=1+x+\frac{x^2}{2!}+\frac{x^3}{3!}....\]

OpenStudy (2bornot2b):

This is it..

OpenStudy (anonymous):

lol, that much we know

OpenStudy (2bornot2b):

Now I hope you get my question?

OpenStudy (anonymous):

I belive you are asking why is something true for real but now for complex?

OpenStudy (2bornot2b):

If that is the definition for real variable, why is the definition for a complex variable such?

OpenStudy (2bornot2b):

Not exactly that, I was asking the reason why the person who first defined that thing, defined it that way..

OpenStudy (2bornot2b):

I mean why\[e^{x+iy}\] is equal to \[e^x(cos(y)+isin(y))\] and not something else?

OpenStudy (anonymous):

I finally got you , hold on

OpenStudy (anonymous):

http://www.youtube.com/watch?v=N4ceWhmXxcs

OpenStudy (anonymous):

imranmeah91 - that is a good video! I loved it. Are you doing MIT Open Course Ware?

OpenStudy (saifoo.khan):

Hey Gt?

OpenStudy (anonymous):

Hey Saifoo!

OpenStudy (saifoo.khan):

Hi, im really sorry i was unable to reply on fb, i just did now! ^_^

OpenStudy (anonymous):

No worries. It was not an urgent issue.

OpenStudy (anonymous):

BTW - I just got to "Super Hero" status. Fun! :-) Don't know what it really means. But, interesting that I could get there in such a short time.

OpenStudy (saifoo.khan):

Congrats.. it's like for each 10 levels u will get new status.. But as more u go forward.. u need more points to get to another level.

OpenStudy (anonymous):

Seems like it. Because at 50 level, it is slow moving to 51. However, I am surprised that it is not really based on difficulty of questions answered, but the number of questions answered.

OpenStudy (saifoo.khan):

Yes, Right. that's how i got to 100. lol.

OpenStudy (anonymous):

You guys are good and sharp on trignometry and calculus. I am really rusty (25 years ago done it). But, the point system works same for both.

OpenStudy (saifoo.khan):

Agree.. im leaning Calc 2 these days..

OpenStudy (anonymous):

Let us keep in touch. I am going to sign off. Got to catch a plane tomorrow to California.

OpenStudy (saifoo.khan):

Oh, Kewl. u may read the message!! ^_^

OpenStudy (anonymous):

will do. bye.

OpenStudy (saifoo.khan):

Byee.

OpenStudy (jamesj):

2b: thanks for the message. hopefully that video gives you what you need.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!