Question

let f(x)=3^x- x^3. find the values of x such that the tangent to the curve is parallel to the secant through (0, 1) and (3, 0). please help and show all steps!

Answer 1

first we need the slope of the secant line, which can be found with the old-fashioned formula for the slope of a line\[m={y_2-y_1\over x_2-x_1}\]once we have that slope of the secant line we need to find the values of x for which the derivative of the function has the same value, m:
\[f'(x)=m\]

Answer 2

is the derivative (3^x)(ln3)-3x^2????

Answer 3

yes :)

Answer 4

okay then what is the answer because mine seems wrong