let f(x)=3^x- x^3. find the values of x such that the tangent to the curve is parallel to the secant through (0, 1) and (3, 0). please help and show all steps!

Question

turingtest · Answer

first we need the slope of the secant line, which can be found with the old-fashioned formula for the slope of a line$$m={y_2-y_1\over x_2-x_1}$$once we have that slope of the secant line we need to find the values of x for which the derivative of the function has the same value, m:
$$f'(x)=m$$

anonymous · Answer

is the derivative (3^x)(ln3)-3x^2????

turingtest · Answer

yes :)

anonymous · Answer

okay then what is the answer because mine seems wrong