Question

Hi hero, if you have some time can you help me understand how to solve Quadratic Equations, please?

Answer 1

\[-(-7_)\pm \sqrt{(-7)^{2}-4(3)(-5)} \over2(3)\]

Answer 2

the next step is

Answer 3

\[7\pm \sqrt{109}\over6\]

Answer 4

looks good so far :)

Answer 5

i don't understand the result 109

Answer 6

for instance: i know 7 sq = 49

Answer 7

4 * 3 = 12

Answer 8

4*-5=-20

Answer 9

but they don't add up to 109

Answer 10

you just can't simplify \[\sqrt{109 }\]so just leave it like that

Answer 11

this is sample equation

Answer 12

oh I see what you mean...

Answer 13

lets say the 2nd equation doens't exist: how to I arrive to the results of the 2nd equation

Answer 14

you have that under the radical (which is called the discriminant by the way) is
\[(-7)^2-4(3)(-5)\]right? and you just don't see how that equals 109?

Answer 15

yes!

Answer 16

\[(-7)^2-4(3)(-5)=49+4(3)(5)=49+12(5)=49+60=109\]you maybe just missed the negative in the -5 makes the terms add I'm guessing....

Answer 17

tytytytytyty i needed to see it just like that. tytytytyt

Answer 18

anytime :)