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Evaluate: The limit as theta approaches 0 of sin theta cot 2 theta
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\[\lim_{x\rightarrow 0}\frac{\sin(x)}{\tan(2x)}\] now l'hopital should give it can you use that one?
Were not suppose to know about that rule yet were supposed to do it the other way algebraically
\[\lim_{x\rightarrow 0}\frac{\sin(x)}{\tan(2x)}\] \[=\lim_{x\rightarrow 0}\frac{1}{2}\frac{2x}{\tan(2x)}\frac{\sin(x)}{x}\]
zarkon! hardly recognized you
So the answer is 1/2?
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I've reverted back to a cartoon form yes...the answer is 1/2
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