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calculate the derivative assuming a is a constant: (ax-3)/((x^5)-a)
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use the quotient rule
well i thought thats what i should do and i tried that but i cant seem to get the right answer
i got this as an answer: (ax((x^5)-a)-(ax-3((5x^4)-a)))
f'(x) = (x^5)-a)*( ax-3)*5x^4 ------------------ (x^5 - a)^2
oohh thanks! i was a little off i get what i did now :)
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typo - f'(x) = (x^5)-a)a - ( ax-3)*5x^4 ---------------------- (x^5 - a)^2
now its algebra from now on
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