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Mathematics 22 Online
OpenStudy (anonymous):

calculate the derivative assuming a is a constant: (ax-3)/((x^5)-a)

OpenStudy (anonymous):

use the quotient rule

OpenStudy (anonymous):

well i thought thats what i should do and i tried that but i cant seem to get the right answer

OpenStudy (anonymous):

i got this as an answer: (ax((x^5)-a)-(ax-3((5x^4)-a)))

OpenStudy (anonymous):

f'(x) = (x^5)-a)*( ax-3)*5x^4 ------------------ (x^5 - a)^2

OpenStudy (anonymous):

oohh thanks! i was a little off i get what i did now :)

OpenStudy (anonymous):

typo - f'(x) = (x^5)-a)a - ( ax-3)*5x^4 ---------------------- (x^5 - a)^2

OpenStudy (anonymous):

now its algebra from now on

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