Question

Of the parts produced by a particular machine, 0.6% are defective. If a random sample of 11 parts produced by this machine contains 2 or more defective parts, the machine is shut down for repairs. Find the probability that the machine will be shut down for repairs based on this sampling plan.

Answer 1

Hi there. Do you know the binomial distribution?

Answer 2

no i dont i think that is where i get confused.

Answer 3

what class is this?

Answer 4

I would do this using the binomial distribution, but I don't want to tell you that way if it's not part of what you're supposed to be learning.

Answer 5

i beleive it is using the binomial distribution

Answer 6

OK, so, let's compute the probability that the machine will *not* be shut down. that would be the binomial distribution, with n=11, p=0.006, evaluated at k=0 plus evaluated at k=1.

Answer 7

(the PDF at those two k values, I mean)

Answer 8

\[\mu=np\] is my formula and I need to just plug in the n=11 and p= 0.6 or does it need to be 0.006

Answer 9

0.6% is equal to 0.006, but the formula you gave just tells you the expected number of defective parts, not the probability of finding a particular number of defective parts

Answer 10

thanks for the help i think i am confusing myself more and more trying to figure this out. I will ask my teacher to show me a sample tomorrow.