Question

on this one i just need to know how to set it up...

Answer 1

\[\sum_{k=1}^{50}[(k+1)^2-k^2]\]

Answer 2

i'll solve it if i can just get help setting it up...

Answer 3

your first step is to simplify the equation:

(k+1)(k+1) - k^2 (multiply it all out)

what do you get?

Answer 4

2k+1

Answer 5

great! so now it's a much easier problem. and you'll do it just like the last problem you did.

Answer 6

the sum of a constant is just that constant right?

Answer 7

\[ \sum_{j=1}^n c = nc \]

Answer 8

so my final answer is.... 2600

Answer 9

Yes

Answer 10

SWEET!!!!

Answer 11

\[ \sum_{k=1}^{50} (2k+1) = 2 \sum_{k=1}^{50} k + \sum_{k=1}^{50} 1 = 2 \frac{50(50+1)}{2} + 50 = 2550 + 50 = 2600. \]

Answer 12

that is exactly what i did

Answer 13

good