Question

Find the probability that a randomly chosen point in the figures lies in the shaded region.

Answer 1

I got that P=~1.28

Answer 2

is that right?

Answer 3

144-36pi/144

Answer 4

Ssqr = 12*12=144
Scrcl = 3.14*6*6

P=(12*12)/(pi*6*6)

this is what I did.
it's not right, though is it?

Answer 5

its wrong
subtract the area of the circle from that of the square
then divide that by 144

Answer 6

i got like .215, though

Answer 7

thats riught

Answer 8

No, indian is right. You need to fine the shaded area over the total area.
The shded area=area of the square-area of the circle=\(12^2-6^2\pi\).
The total area=the square area=\(12^2\).

Answer 9

oh ok, thanks you guys! I understand better