Question

write in standard form an equation of the line that passes through the two points. use integer coefficients. FOR (4,9) and (-2,-6)

Answer 1

find the slope first

Answer 2

to find the slope you use (y2-y1)/(x2-x1) you'll get 15/6
put that into the equation y=mx+b and use one of the ordered pairs to put in a y and x value t find what b is

Answer 3

(-6-9)/(-2-4)=(y-9)/(x-4)
5x-2y-2=0

Answer 4

THANK YOU

Answer 5

(-6-9)/(-2-4) = -15/-6 = 15/6
y=mx+b
y=(15/6)x+b
to find b i'll use the coordinates (4,9)
9=(15/6)(4)+b
9=10+b subtracting 10 from both sides
-1=b
so mow you have the equation y=(15/6)x - 1
to turn this into standard form
(-15/6)x + y = -1 divide by -6
15x-6y=6
is that what you got?

Answer 6

yes

Answer 7

okay, if you have an answer key (like at the back of your textbook) check it to make sure you have the right thing

Answer 8

can you help me with another one please?

Answer 9

post it and we'll see

Answer 10

write in standard form an equation of the line that passes through the given point and has the given slope. use integer coefficients. FOR (2,3) m = -4

Answer 11

okay, so put this into the equation y=mx+b again to find b
you'll get 11 and have the equation
y=-4x+11, in standard form this is
4x+y=11
is that what you have?

Answer 12

no i did something wrong

Answer 13

\[y=mx+b\] substitute the x and y for their values (the coordinates)

3=-4(2)+b
3=-8+b add 8 to both sides
11=b
now you have, in slope intercept form, y=-4x+11
in standard form, this is 4x+y=11