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set C = {x:sec^2(3x) = 1, 0<= x <= 180} (degrees) find n(C)
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plot the graph for sec^2(3x) and draw the line y=2 in the same graph, the no. of points of intersection give you n(C)
no, we're supposed to do it algaebricly.
*non-graphically.
sec^2(3x)=1+tan^2(3x)=1, so, all you have to do now is find x, for which tan^2(3x) is zero when 0<=x<=180, which comes down to tan(3x)=0
So, x = 0˚ or x = 180˚, hence n(C) = 2
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no, its tan(3x)=0 not tan(x)=0
so, its actually 4
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