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Mathematics 21 Online
OpenStudy (anonymous):

set C = {x:sec^2(3x) = 1, 0<= x <= 180} (degrees) find n(C)

OpenStudy (anonymous):

plot the graph for sec^2(3x) and draw the line y=2 in the same graph, the no. of points of intersection give you n(C)

OpenStudy (anonymous):

no, we're supposed to do it algaebricly.

OpenStudy (anonymous):

*non-graphically.

OpenStudy (anonymous):

sec^2(3x)=1+tan^2(3x)=1, so, all you have to do now is find x, for which tan^2(3x) is zero when 0<=x<=180, which comes down to tan(3x)=0

OpenStudy (kira_yamato):

So, x = 0˚ or x = 180˚, hence n(C) = 2

OpenStudy (anonymous):

no, its tan(3x)=0 not tan(x)=0

OpenStudy (anonymous):

so, its actually 4

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