prove that (2+2sinx)/cosx = 2secx ???
what have you tried ?
is this really \[\frac{2+2\sin(x)}{\cos(x)}=2\sec(x)\]?
this is crazy....
yup. so we don't need to solve it, only prove it. I had a bigger equation which I managed to simplify to the above, and I need it to equate to 2secx. I'm confused :P
because \[\frac{2+2\sin(x)}{\cos(x)}=\frac{2}{\cos(x)}+\frac{2\sin(x)}{\cos(x)}=2\sec(x)+2\tan(x)\] and this is certainly not \[2\sec(x)\] unless of course \[\tan(x)=0\]
maybe you could post the original problem, because this is not correct
I had a bigger equation which I managed to simplify to the above, and I need it to equate to 2secx .... you should just type the whole equation ... hjahaha
okayy, lemme post the original question, okayy??? \[cosx/(1-sinx) + cosx/(1+sinx) = 2secx\] Prove this.
how'd i guess?
not bad, broo.
numerator is \[\cos(x)(1+\sin(x))+\cos(x)(1-\sin(x))=2\cos(x)\] denominator is \[1-\sin^2(x)=\cos^2(x)\]and then you are done by canceling
This is too easy, you should really try it out.
YUCK. I multiplied both the numerators with 1 + sinx, and not 2 different ones. YUCK. SLAP ME, SOMEONE.
xD
Slap slap slap ..
THANK YOU.
I got the answer. its easy. NCERT exercise type problem. To Prove: cos x/ (1 - sin x) + cos x/(1+ sin x )= 2 sec x Proof: Cross multiplying, we get, (cos x + cos x sin x + cos x - cos x sin x)/[ (1- sin x)(1 + sin x)] = 2 cos x/(1 - sin square x)= 2 cos x/ cos x cos x= 2/ cos x = 2 sec x= RHS Hence Proved.
Thanks FFM. Cheers
Join our real-time social learning platform and learn together with your friends!