The Steamboat aloftser in Yellowstone National Park, Wyoming is capable of shooting its hot water up from the ground with a speed of 48.0 m/s. How high can this aloftser shoot? (HINT: USE KINEMATIC EQUATIONS)

Question

anonymous · Answer

1/2 m v^2= m g h

1/2 v^2 = g h

1/2 v^2
-------  =h
g

anonymous · Answer

Um... could you explain please because it doesnt look like something I learned before

anonymous · Answer

There is something called conservation of energy. 

So in the beginning all the energy were kinetic(moving energy) = 1/2 m v^2

when it is at the top , all the energy is potential()  = mgh

they should be the same because of energy conservation

1/2 mv^2 = m gh

mass(m) cancels out

anonymous · Answer

1/2 v^2= gh

1/2 v^2
-------  =h
g

anonymous · Answer

Or you can use one of the kinetic equaton
$$(v_f)^2=(v_i)^2 - 2 g h$$

at the top $$v_f=0$$

$$0=(v_i)^2 - 2 g h$$

$$h=(v_i)^2/2g $$