10. Twenty-four percent of the patients who take the drug “VIAGRO” suffer from side effects such as runny nose, diarrhea and upset stomach. If n patients at the hospital take VIAGRO, the probability that at most one patient will suffer side effects will be
what is n?
the probability that any patient does not suffer is 0.76 the probability that all n patients to not suffer is \[0.76^n\]and the probability that "at least one patient suffers" is 1 - the probability that no patient suffers is \[1-0.76^n\]
n outcomes in the sample space. 1 successful outcome. Probability = 1/n
hmm maybe my answer was wrong. at most one means 0 or 1, so you have to compute the probabiity of none, which is \[.76^n\] and the probability of 1 which is \[n\times 00.24\times 0.76^{n-1}\] and add them
You need to use the following equation where n is the total and r is the number of patients. The probability will be for r=1 and 0 P=nCr (p^r)(p-1)^(n-r) P= P(1) + P(0) = nC1 (0.24)^1 * (0.76)^(n-1) + nC0 (0.24)^0 * (0.76)^(n-0) = 0.24n*(0.76)^(n-1) + 0.76^n
Sorry the rule I wrote is off P=nCr (p^r)(1-p)^(n-r) It should be 1-p
right. what zed said. i was wrong and zed is right. it is \[.076^n +n\times 0.24\times 0.76^{n-1}\]
typo there should be \[0.76^n +n\times 0.24\times 0.76^{n-1}\]
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