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A student club has 11 members. How many ways can the club choose a president, vice president, and treasurer? A. 330 B. 990 C. 165 D. 1,650
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Solve this by asking yourself: How many people can be chosen for president: After a president have been chosen, how many are left standing for vice president? After you chose the vice, how many remain for the treasurer? Use that logic to solve it
P(n,r) = (n!)/((n-r)!) P(11,3) = (11!)/((11-3)!) P(11,3) = (11!)/(8!) P(11,3) = (11*10*9*8!)/(8!) P(11,3) = 11*10*9 P(11,3) = 990 So there are 990 ways
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