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OpenStudy (vishal_kothari):

Seven people are in an elevator which stops at ten floors. In how many ways can they get o the elevator...

OpenStudy (vishal_kothari):

get*off*the

OpenStudy (nubeer):

not sure maybe 10! x 7!

OpenStudy (vishal_kothari):

no..

OpenStudy (anonymous):

\( 11^7 \) ?

OpenStudy (vishal_kothari):

no..

OpenStudy (anonymous):

what is the answer ?

OpenStudy (anonymous):

@across: I don't think that's the right answer.

OpenStudy (vishal_kothari):

(a) 7^10 (b) 10^7

OpenStudy (vishal_kothari):

answer lies between this two...

OpenStudy (anonymous):

answer is \( 10^7 \) then.

OpenStudy (anonymous):

Oh, I think the answer that across gave assumed that each one gets off in a different floor?

OpenStudy (vishal_kothari):

how?

OpenStudy (anonymous):

The problem is modeled as " how many ways can n distinct object can be divided in r distinct groups " some groups may be empty.

OpenStudy (anonymous):

My earlier answer assumes the super-set and I over counted few other cases.

OpenStudy (across):

FFM is correct.

OpenStudy (vishal_kothari):

ya..

OpenStudy (across):

Think of it in smaller terms: suppose there are three floors and two people; they can get off the elevator in 9 different ways, which is \(3^2\) as FFM's model states.\[\]

OpenStudy (anonymous):

Precisely, my earlier answer assumes that the seven people need not to get off the elevator at all and only some of them get down and all of the other obvious cases.

OpenStudy (anonymous):

@across: wanna try a variation " atleast one should get off in each floor" ? ; )

OpenStudy (vishal_kothari):

ok..

OpenStudy (across):

In this case, though, there are more floors than there are people. :p

OpenStudy (anonymous):

@vishal kothari: It's a bit hard, don't attempt it if you don't need it.

OpenStudy (anonymous):

@across: well just increase the numbers :P

OpenStudy (across):

Let's try 7 floors and 10 people.

OpenStudy (anonymous):

or more generally any \( r \gt n \)

OpenStudy (anonymous):

Sorry it should be: or more generally any \( r<n \) pertaining to my above model.

OpenStudy (across):

Whoops.

OpenStudy (anonymous):

@across: Sorry, that doesn't seem correct, as \( n^{ \underline{r} } \) is not the correct assumption, generally people attempt it with mutual inclusion-exclusion, but there is a even clever way, If you want I can give you a hint but it would be probably a spoiler.

OpenStudy (pokemon23):

anyone willing to explain me about square roots?

OpenStudy (anonymous):

Anyways, always excuse my solecism :P

OpenStudy (anonymous):

Assume that the elevator riders are considered indistinguishable, for example, 7 warm bodies. There are 11440 ways for them to get off of an elevator servicing 10 floors. http://2000clicks.com/mathhelp/CountingObjectsInBoxes.aspx Refer to: Indistinguishable Objects to Distinguishable Boxes The number of different ways to distribute n indistinguishable balls into k distinguishable boxes is C(n+k-1,k-1). For those who have access to Mathematica the following is a user defined function called Elevator where r is the number of riders and f is the number of floors. Elevator[ r_ , f_ ] := Binomial[ r + f - 1, f - 1]

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