What is the solution to the equation 49x=sqrt 7^(2x+6)
49x or 49^x ?
49^x ,sorry
Notice first then that because 49 = 7^2, that 49^x = 7^(2x).
yes? Now square both sides: \[ 7^{4x} = 7^{2x+6} \] making sense?
sort of
So first, happy with 49^x = 7^2x ?
yes i understand that part
\[ 49^x = (7^2)^x = 7^{2x} \] Now that is equal to \[ \sqrt{7^{2x+6}} = (7^{2x+6})^{1/2} \]
okay
and that is equal to \[ 7^{(2x+6)/2} = 7^{x+3} \]
Hence the original equation \[ 49^x = 7^{2x+6} \] implies \[ 7^{2x} = 7^{x+3} \] because \[ 49^x = 7^{2x} \] and \[ \sqrt{7^{2x+6}} = 7^{x+3} \]
okay
the original equation has a square root I dropped.
So now we have \[ 7^{2x} = 7^{x+3} \] what does that imply?
umm, idk
if \[ 7^a = 7^b \] what can you say about a and b?
they are equal
Yes, a = b. Hence if \[ 7^{2x} = 7^{x+3} \] what can you say.
they are equal also
what's equal? make it explicit; write down the equation.
\[ 7^a = 7^b \ \implies \ a = b \] hence \[ 7^{2x} = 7^{x+3} \ \implies \ ...what? \]
still there?
i need help on this to. so your saying 2x = x +3??
Yes
This helped me so much! Thanks for taking the time to answer this for her!
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