HELP*logs*!!!! asap please!! Solve 2 (^x + 3) = 7
\[2^{x+3}=7\] take ln of both sides \[ln (2^{x+3})=ln(7)\] log rules \[(x+3)ln (2)=ln(7)\] \[(x+3)=ln(7)/ln(2)\] \[(x)=ln(7)/ln(2) -3\]
i solved that...still didnt come up with the answer.. what result did you come up with??
well , my last line was the answer
can you give as a decimal
x ≈ –0.19 x ≈ 0.94 x ≈ –5.19 x ≈ 2.81
Dude / Dudette - you need to learn to use calculator for it.
i am using calc, just dont know how to find as decimal
i got it, -.19
x approximately equals 0.19 seems to be the answer.
can u help me with my other log problem please
Just in case, is the question 2 (^x + 3) = 7 or is it (2^x)+3 = 7
It is 2^(x+3)
It is being written down in a very weird way by the person asking the question. But, that is the idea!
Sorry, just to make sure, sometime the parentheses are added on by the poster because of the superscripts. So there is a chance of transcription error.
Not in this case. We confirmed.
Oh! Thanks and sorry for the interruption.
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