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Mathematics 13 Online
OpenStudy (anonymous):

To be a polynomial expression we need to have +ve whole number exponent, but is x^2/2 a polynomial ?

OpenStudy (anonymous):

yes, because 2/2 is 1 which is a positive whole number.

OpenStudy (anonymous):

What about x+1/x+1 ?

OpenStudy (anonymous):

you mean |dw:1324716236424:dw|

OpenStudy (anonymous):

no, because 1/x is nothing but x^-1

OpenStudy (anonymous):

(x+1)/(x+1) ?

OpenStudy (anonymous):

yes because (x + 1)/(x + 1) = 1

OpenStudy (anonymous):

No I think they cancel out to make 1 a constant....1=x^0

OpenStudy (anonymous):

note that a polynomial doesn't need to have a variable.

OpenStudy (anonymous):

does it?

OpenStudy (anonymous):

nice point mathbug......

OpenStudy (anonymous):

I'm not sure about (x + 1)/(x + 1)

OpenStudy (anonymous):

What about when you graph them, will they have smooth curve and no sharp edges, as polynomial should not have ?

OpenStudy (anonymous):

I don't think x^0 is a polynomial because the exponent should be a whole POSITIVE number.

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