Question

Can someone explain me how to find DE of y=e^(Cx)?

Answer 1

DE means

Answer 2

differential equations

Answer 3

C e^(Cx)

Answer 4

dy/dx
= d(e^(Cx))/dx
=d(e^(Cx))/d(Cx) . d(Cx)/dx
=e^(Cx) . C
=C e^(Cx)

Answer 5

the answer is y' = y*lny/x

Answer 6

is it ? I am not sure about what you have written

Answer 7

it say so in the book

Answer 8

?

Answer 9

i dont understand....its says that i have to find equation, which solution is y= e^(cx)

Answer 10

so, as far as I know,
y' = Ce^(Cx)

Answer 11

i got the same result

Answer 12

so probably something is wrong with your book or something is wrong with both of us

Answer 13

Well you can see that
\[y(x) = e^{Cx} \]
implies that
\[y'(x) = Ce^{Cx} = Cy\]
But apparently your book would like to get rid of explicit mention of C.
\[\ln(y) = \ln(e^{Cx}) = Cx\]
so \[C = \frac{\ln(y)}{x} \]
and so plugging that in,
\[y'(x) = y\cdot \frac{\ln(y)}{x} \]

Answer 14

y=e^(Cx)
y'=Ce^(Cx)

Answer 15

Don't seem alot of questions that make you go backwards on differential equations