Question

the sum of the length and girth of a rectangular box must be smaller than 96 in if the girth is 1/2 of the length,what is the length?

Answer 1

64 inches

Answer 2

x+0.5x = 96
then solve :)

Answer 3

smaller-than, so solve\[\ell+g<96\to\ell+\frac{\ell}{2}<96\]

Answer 4

lost on both

Answer 5

ok i add

Answer 6

i got 64.5

Answer 7

let the length be l
let the girth be g
we are told that the sum of the length and girth must be "less-then" 96, so\[\ell+g<96\]we are also told that the girth is 1/2 the length, so\[\frac{\ell}{2}=g\]sub this into the expression above and we get\[\ell+\frac{\ell}{2}<96\]

Answer 8

\[\ell+\frac{\ell}{2}=\frac{3\ell}{2}<96\]which leads to\[\ell<\frac{2}{3}\times96\]so what do you get for length?

Answer 9

64.5?

Answer 10

am i right plz

Answer 11

I just can;t imagine where you get the .5 from...\[\frac{2}{3}\times96=64\](exact)
so what did you do?

Answer 12

the calculator again:(

Answer 13

ok i multiplied 2/3 by 96 an got 64

Answer 14

thx :)

Answer 15

do the pieces separately
\[96\times2=192\]\[\frac{192}{3}=64\]but remember that this is talking about our expression\[\frac{3\ell}{2}<96\]so the solution is\[\ell<64\]it is important to keep the less-than sign, it's not an equality!

Answer 16

can u check 1 more problem for me i answered it but not sure if im right its the 1 about the area rug?

Answer 17

sure thing :)