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Mathematics 12 Online
OpenStudy (turingtest):

Harder question: Binary perfection. Can a number consisting of 300 ones and some number of zeros be a perfect square? Explain your answer.

OpenStudy (turingtest):

moneybird taught me the trick on these...

OpenStudy (anonymous):

Explain pls.

OpenStudy (turingtest):

you mean the answer? No, the problem hasn't been up long enough.

OpenStudy (anonymous):

Pumas campeón!

OpenStudy (anonymous):

Thinking....

OpenStudy (turingtest):

I'm gonna see if Jyqft has something doable this time...

OpenStudy (anonymous):

No-idea

OpenStudy (turingtest):

It was destined for meta-math anyway, but I know moneybird will solve it if I put it there...

OpenStudy (anonymous):

This number is divisible by 3 (because of the divisibility rule) but not by 9. Therefore it cannot be a perfect square. :)

OpenStudy (turingtest):

Yeah TracysaurusRex, that's it! I didn't know about that rule until I came on this site.

OpenStudy (anonymous):

wow that is very nice rule,

OpenStudy (turingtest):

moneybird referenced the rule used above as a special case of this theorem, which I had never heard of either: http://answers.yahoo.com/question/index?qid=20080716092006AAWNZNu

OpenStudy (turingtest):

Not sure I see the connection though, but I'm sure it's insightful.

OpenStudy (anonymous):

i think that rule is simply because of the fact that a perfect square must have only 2 factors 1 and the number itself, and if a number is a multiple of threee, 3 must come in its prime factorization, and it must come even number of times, hence it hasto be a multiple of nine to be a perfect square, as far as that theorem is concerned, it is elegant

OpenStudy (mathmate):

Stom, you were probably thinking of primes! A perfect square has to have an ODD number of factors, like 100 has 1,2,5,10,20,50,100.

OpenStudy (anonymous):

what i meant was a perfect squares must have only 2 factore 1 and the number itself, the number itself can have its own factors as well, thats not a n issue at all,

OpenStudy (mathmate):

Just in case it's relevant, is the number in base 10 or base 2?

OpenStudy (turingtest):

It sounds like it should be binary now that you mention it, but the answer is what TracySaurus gave, so it must be base 10 I suppose.

OpenStudy (turingtest):

By "binary" they must just mean the fact they are using two numbers, not as a base.

OpenStudy (mathmate):

Oh great, so that was the official answer, and it makes sense too.

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